SOLUTION: (8x^2 - 18x + 9) (x - 9)= 0
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Question 39712
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(8x^2 - 18x + 9) (x - 9)= 0
Answer by
tran3209(100)
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(8x^2-18x+9)(x-9)=0
(4x-3)(2x-3)(x-9)=0
4x-3=0---->x=3/4
2x-3=0---->x=3/2
x-9 =0---->x=9
The answers are: x=3/4, x=3/2 and x=9