Question 397089: The sum of 3 numbers is 49. The 2nd number is 5 minus 2 times the 1st number. The 3rd number is 6 minus the 1st number. What are the numbers?
Answer by Sarpi(32)   (Show Source):
You can put this solution on YOUR website! Solution
Let X1,X2 and X3 denote the three numbers.
=> X1= x
X2= 5-2*x "5 minus 2 times the first number"
X3= 6-x "6 minus the first number"
Therefore the sum of these three numbers should be equal to 49.
=> X1+X2+X3=49
x+(5-2x)+(6-x)=49
x+5-2x+6-x =49
x-2x-x =49-5-6
-2x=38
x =38/-2 which is -19.
So the first number is -19,
the second number is 5-2x
=5-2(-19)
=43
and the third number is 6-x
=6-(-19)
=6+19
=25
Thus by checking;
The sum of the three numbers is -19+43+25 which is indeed equal to 49.
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