SOLUTION: Divide. 7x^5y^5 - 21x^4y^4 + 14x^3y^3 divided by xy^2z^3
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Question 39688
This question is from textbook
Beginning Algebra
:
Divide.
7x^5y^5 - 21x^4y^4 + 14x^3y^3 divided by xy^2z^3
This question is from textbook
Beginning Algebra
Answer by
fractalier(6550)
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Okay, we treat this as three separate little probems, so we get
(7x^5y^5 - 21x^4y^4 + 14x^3y^3) / (xy^2z^3) =
(7x^4y^3 - 21x^3y^2 + 14x^2y) / z^3
that's as far as we can go...