SOLUTION: Solve the following system of linear inequalities by graphing. 3x - y < 2 and x + y > 2 I can come up with several solution sets for both, but none for a consistent sy

Algebra ->  Inequalities -> SOLUTION: Solve the following system of linear inequalities by graphing. 3x - y < 2 and x + y > 2 I can come up with several solution sets for both, but none for a consistent sy      Log On


   

Question 39673: Solve the following system of linear inequalities by graphing.
3x - y < 2 and x + y > 2
I can come up with several solution sets for both, but none for a consistent system. Any suggestions?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
3x - y < 2 and x + y > 2
add y to each side of the 1st one
3x < 2 + y
subtract 2 from both sides
3x - 2 < y
rewrite with y on the left
y > 3x - 2
--------------------------
subtract x from both sides oof 2nd one
y > -x + 2
graph these as equalities
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+3x+-+2%2C+-x+%2B+2%29+
The solution set should be the "V" shaped area above both lines
Let's test this
The points (1,4) and (-4,7) look like they fall in this area
always go back to original statements to check
3(1) - 4 < 2
TRUE
1 + 4 > 2
TRUE
3(-4) - 7 < 2
TRUE
-4 + 7 > 2
TRUE