Question 396503: A collection of nickels and dimes total $5.95. If there are 5 times as many nickels as dimes, then how many of each coin is there? Found 2 solutions by stanbon, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A collection of nickels and dimes total $5.95. If there are 5 times as many nickels as dimes, then how many of each coin is there?
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Quantity Eq: n = d + 5
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Value Eq: 5n + 10d = 595 cents
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Substitute for "n" and solve for "d":
5(d+5) + 10d = 595
15d + 25 = 595
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15d = 570
d = 30 (# of dimes)
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Solve for "n":
n = d +5
n = 30+5
n = 35 (# of nickels)
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Cheers,
Stan H.
You can put this solution on YOUR website! A collection of nickels and dimes total $5.95. If there are 5 times as many nickels as dimes, then how many of each coin is there?
Let the amount of dimes be D
Then the amount of nickels are 5D
Since the coins total $5.95, we then have: .1(D) + .05(5D) = 5.95
.1D + .25D = 5.95
.35D = 5.95
Therefore, D or dimes = =
and nickels = 17 * 5 =
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Check
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Dimes: 17 = 17 * 10_______$1.70
Nickels: 85 = 85 * 5______$4.25
Total of coins___________$5.95
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