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Question 396387: Problem: The last of three consecutive numbers increased by ten is equal to the sum of the first two consecutive numbers.
Here is what i have so far:
Let 1st number = x
2nd number = x+1
3rd number = x+2
3x+3 now I need to increase it by 10.
3x+3+10 re-written as 3x+13
3x+13= to the sum of the first two consecutive numbers.
which is 3x+13=x+x+1 re-written as 3x+13=2x+1
when I solved I got x=-12 is this correct? what am I doing wrong??
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! The last of three consecutive numbers increased by ten is equal to the sum of the first two consecutive numbers.
Here is what i have so far:
Let 1st number = x
2nd number = x+1
3rd number = x+2
It says,"The last of three consecutive numbers increased by ten ", that would be:
(x+2) + 10 = x+12
"is equal to the sum of the first two consecutive numbers."
x + 12 = x + (x+1)
x + 12 = 2x + 1
12 - 1 = 2x - x
11 = x
:
11, 12, 13 are the numbers
Check it in the statement:
"The last of three consecutive numbers increased by ten is equal to the sum of the first two consecutive numbers."
13 + 10 = 11 + 12
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