SOLUTION: what are the zeros of f(x)= 1/2x^2+5/2x-3/2

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Question 396125: what are the zeros of f(x)= 1/2x^2+5/2x-3/2
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)= 1/2x^2+5/2x-3/2
f(x)=.5x^2+2.5x-1.5
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(-2.5+-sqrt[2.5^2-4*.5*-1.5))/2*.5
x=(-2.45+-sqrt[6.25+3])/1
x=(-2.5+-sqrt9.25)
x=(-2.5+-3.04)
x=-2.5+3.04
x=.54 ans.
x=-2.5-3.04
x=-5.46 ans.