Question 3959: mr.armstrong is saving his change in al large glass jar to buy a new hockey stick. yesterday,he counted the coins in the jar and found out that he only had quarters and dimes. there were a total of 345 coins.if he saved $75.90 how many quartes and dimes would he have?
plz show complete solution. thanks
Answer by guapa(62)   (Show Source):
You can put this solution on YOUR website! We have a total amount of 345 coins.Let q represent the number of quarters. Then 345-q represents the number of dimes. Use the following guideline to set up the equation:
Value of quarters in cent + Value of nickels in cents = Total value in cents
25q + 10(345-q) = 7590
(25 because 1 quarter has 25 cents and 10 because 1 dime has 10 cents)
Now let's solve this equation:
25q+10(345-q)=7590
25q+3450-10q=7590 Now just combine like terms and substract 3450 from both sides.
15q+3450-3450=7590-3450
15q=4140
q= 4140/15
q=276
If q= 276, then 345-276=69, so he has 276 quarters and 69 nickels
Check:
276*25=6900/100 = $69
69*10=690/100 = $6.90
$69,00 + $6.90 = $75.90
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