SOLUTION: if log 3=m and log 2=n, find log (600) in terms of m and n

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: if log 3=m and log 2=n, find log (600) in terms of m and n      Log On


   

Question 395796: if log 3=m and log 2=n, find log (600) in terms of m and n
Found 3 solutions by Alan3354, lwsshak3, richard1234:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
600 = 2*3*10*10
log(600) = log(m) + log(n) + 2

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
if log 3=m and log 2=n, find log (600) in terms of m and n
600 = 2*3*100
=2*3*10^2
using multiplication and power rule for logs
log600 =log2+log3+2log10

log of the base =1
ans: log 600 =n+m+2

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
log 600 = log (100*3*2) = log 100 + log 3 + log 2 = 2 + m + n