SOLUTION: find three consecutive even integers such that twice the sum of the first and third is twelve more than twice the second

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Question 395771: find three consecutive even integers such that twice the sum of the first and third is twelve more than twice the second
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
If the integers are a, a+2, and a+4, then

2%28a+%2B+a+%2B+4%29+=+2%28a%2B2%29+%2B+12

4a+%2B+8+=+2a+%2B+16

a+=+4

The integers are 4, 6, 8.