SOLUTION: Greg's first three test scores were consecutive even integers. His fourth score was 76. If his test average on the four test scores was between 82 and 84, what was his lowest pos
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-> SOLUTION: Greg's first three test scores were consecutive even integers. His fourth score was 76. If his test average on the four test scores was between 82 and 84, what was his lowest pos
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Question 395510: Greg's first three test scores were consecutive even integers. His fourth score was 76. If his test average on the four test scores was between 82 and 84, what was his lowest possible test score?
This is what I tried:
Let X= score of first test
test 1: x
test 2: x+2
test 3: x+4
test 4: 76
82< [x+(x+2)+(x+4)+76] /4 <84
82< (3x+82) /4 <84
328< 3x +82 <336
246< 3x <254
82 < x <84.666
I don't know what I did wrong/ how to finish it. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Greg's first three test scores were consecutive even integers.
You have to symbolize even integers as multiples of 2.
1st: 2x-2
2nd: 2x
3rd: 2x+2
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His fourth score was 76.
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If his test average on the four test scores was between 82 and 84, what was his lowest possible test score?
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Inequality:
82 < [2x-2+2x+2x+2+76]/4 < 84
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82 < [6x+76]/4 < 84
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328 < 6x+76 < 336
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252 < 6x < 260
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42 < x < 43 1/3
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His test scores:
2x-2 = 2*43-2 = 84
2x = 86
2x+2 = 88
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76 is the lowest of the 4 scores.
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Cheers,
Stan H.
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