SOLUTION: the square root of the sum of two consecutive integers is eleven. find the larger integer?

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Question 395435: the square root of the sum of two consecutive integers is eleven. find the larger integer?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the square root of the sum of two consecutive integers is eleven. find the larger integer?
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The sum of 2 consecutive integers = 121.
121/2 = 60.5
--> 60 & 61

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
the square root of the sum of two consecutive integers is eleven.
find the larger integer?
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sqrt(x+x+1) = 11
x+x+1 = 121
2x = 120
x = 60
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x+1 = larger = 61
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Cheers,
Stan H.