SOLUTION: Which of the following is equivalen to sin(data)+cot(data)cos(data) F)2sin(data) G1/sin(data) H)cos^2(data) J)sin(data)+cos(data)/sin^2(data) The key is G

Algebra ->  Probability-and-statistics -> SOLUTION: Which of the following is equivalen to sin(data)+cot(data)cos(data) F)2sin(data) G1/sin(data) H)cos^2(data) J)sin(data)+cos(data)/sin^2(data) The key is G       Log On


   

Question 395358: Which of the following is equivalen to sin(data)+cot(data)cos(data)
F)2sin(data)
G1/sin(data)
H)cos^2(data)
J)sin(data)+cos(data)/sin^2(data)
The key is G

Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Recall that cot(x)=1/tan(x) and that tan(x)=sin(x)/cos(x)


So this means that cot(x)=cos(x)/sin(x)


So

sin(x)+cot(x)cos(x) = sin(x)+(cos(x)/sin(x))cos(x)

sin(x)+cot(x)cos(x) = sin(x)+cos^2(x)/sin(x)

sin(x)+cot(x)cos(x) = sin^2(x)/sin(x)+cos^2(x)/sin(x)

sin(x)+cot(x)cos(x) = (sin^2(x)+cos^2(x))/sin(x)

sin(x)+cot(x)cos(x) = 1/sin(x)


So the answer is choice G


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
sin%28data%29%2Bcot%28data%29cos%28data%29

since cot+%28data%29+=+%28cos+%28data%29%29%2F%28sin+%28data%29%29

sin%28data%29%2B%28%28cos+%28data%29%29%2F%28sin+%28data%29%29%29cos%28data%29

sin%28data%29%2B%28%28cos+%28data%29%29%5E2%2F%28sin+%28data%29%29%29

%28cos+%28data%29%29%5E2=+1+-%28sin+%28data%29%29%5E2

sin%28data%29%2B%281+-+%28sin+%28data%29%29%5E2%29%2F%28sin+%28data%29%29%29%29......common denominator







1+%2F%28sin+%28data%29%29