SOLUTION: the width of a box is 9 inches more than its length. the height of the box is 1 inch less than its length. if the box has a volume of 72 cubic inches, what are the dimensions of th

Hi

Letting x, (x-1)(x+9) represent the length, height and width respectively

Question states***

 x(x-1)(x+9)= 72 in^3

solving for x

 x^3 + 8x^2 - 9x - 72 = 0  |x = 3 is one solution found by substitution

(x-3)(x^2 + 11x + 24)= 0   |dividing  (x^3 + 8x^2 - 9x - 72) by (x-3)

factoring the quadratic

(x-3)(x+3)(x+8) = 0   |tossing negative solutions out for length

 x = 3

Dimensions of the box are 3in long, 2in high, 12in wide