Question 39529: Suppose that the tempature outside is dropping at a constant rate.At noon, the tempature is 70 F,and it drops to 58F at 5pm ..How much did the tempature change each hour?
I thought it was half hour ,but i was wrong.Sorry the 5 did not come up in my other post.
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! Well, we can logic it out...
If the temperature drops from 70 to 58, it dropped 12 degrees.
If it took 5 hours, then we divide 12 degress by 5 hours, and get
12 / 5 = 2.4 degrees per hour
We can look at it another way too...
(70 - 58) / (5 - 0) = 2.4
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