SOLUTION: Rewrite the equation y=–2x^2-4x+3 in vertex form. Identify the vertex and the axis of symmetry.

Hi

the vertex form of a parabola,  where(h,k) is the vertex

y = –2x^2-4x+3         |completing square to put into vertex form

y = –2[x+1)^2 -1]+3 

y = –2(x+1)^2 +5  Vertex Pt(-1,5)  Axis of symmetry is x = -1