SOLUTION: find three consecutive integers such that the product of -5 and the sum of the first two is 43 less than twice the second.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive integers such that the product of -5 and the sum of the first two is 43 less than twice the second.      Log On


   

Question 394707: find three consecutive integers such that the product of -5 and the sum of the first two is 43 less than twice the second.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x, (x+1), (x+2) represent the three consecutive integers

Write as we Read***

 -5[ x + (x+1)] = 2(x+1) -43

solving for x

  -10x - 5 = 2x - 41

        36 = 12x

         3 = x   The three consecutive integers are 3,4,5

CHECKING our Answer***

 -5*7 = 2*4 - 43 = -35