SOLUTION: I need the last two digits from the following numbers 11^2011. I need all work t be shown please, so I can fugure out how to do my other problems, PLEASE and super huge thank you!!
Algebra ->
Exponents
-> SOLUTION: I need the last two digits from the following numbers 11^2011. I need all work t be shown please, so I can fugure out how to do my other problems, PLEASE and super huge thank you!!
Log On
Question 394614: I need the last two digits from the following numbers 11^2011. I need all work t be shown please, so I can fugure out how to do my other problems, PLEASE and super huge thank you!! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! I need the last two digits from the following numbers 11^2011.
-------------------
The last 2 digits are cyclic, and are equal to the exponent modulo 10.
For exponents from 1 to 10, they are:
11
21
31
41
51
61
71
81
91
01
Then they repeat.
2011/10 = 201 remainder 1, so the last 2 digits are the same as 11^1
= 11.
