SOLUTION: how do you solve x=2y+2 2x+3y=11 using substitution

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Question 394307: how do you solve
x=2y+2
2x+3y=11
using substitution
Found 2 solutions by MathLover1, ewatrrr:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

x=2y%2B2....or....x+-+2y+=+2

now solve the system:
x+-+2y+=+2
2x+%2B+3y+=+11


Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+-2%5Cy+=+2%2C%0D%0A++++2%5Cx+%2B+3%5Cy+=+11+%29%0D%0A++We'll use substitution. After moving -2*y to the right, we get:
1%2Ax+=+2+-+-2%2Ay, or x+=+2%2F1+-+-2%2Ay%2F1. Substitute that
into another equation:
2%2A%282%2F1+-+-2%2Ay%2F1%29+%2B+3%5Cy+=+11 and simplify: So, we know that y=1. Since x+=+2%2F1+-+-2%2Ay%2F1, x=4.

Answer: system%28+x=4%2C+y=1+%29.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

using substitution to solve

x=2y+2

2x+3y=11

substituting (2y+3) for x

2(2y+2) + 3y = 11

solving for y

4y + 4 + 3y = 11

     7y = 7

      y = 1 and 

      x = 4       | x = 2y + 2= 2*1+2 = 4

One solution (4,1)