SOLUTION: the diiference betwwen two numbers is 10. when eight times the smaller number is added to 40, the result is ten less than three times the larger number. find both numbers

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Question 394079: the diiference betwwen two numbers is 10. when eight times the smaller number is added to 40, the result is ten less than three times the larger number. find both numbers
Answer by pie90010(44) About Me  (Show Source):
You can put this solution on YOUR website!
x+-+y+=+10
3x+-+10+=+8y+%2B+40
x is the larger number in this case
so break down the second one, so you can line it up
3x+-+10+=+8y+%2B+40
3x+-+8y+=+50
1x+-+1y+=+10
multiply the second equation by -3, so you can cancel the X's
-3x+%2B+3y+=+-30
+3x+-+8y+=++50
add them up
-5y+=+20
y+=+-4
now that you have y, just plug it into the original equation to get x
x+-+y+=+10
x+-+%28-4%29+=+10
x+%2B+4+=+10%29
x+=+6
so the solution would be
(6,-4)