SOLUTION: Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy?

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Question 393818: Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy?
Found 2 solutions by ankor@dixie-net.com, Alan3354:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Tracy leaves for work at 8am, traveling at 36mph.
Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch.
At what time will Sarah catch Tracy?
:
Change 5 min to hr: 5/60 = .0833 hrs
:
Let t = Sarah's travel time
then
(t+.0833) = Tracey's travel time
:
When S catches T they will have traveled the same distance
Write a distance equation: d = speed * time
:
50t = 36(t+.0833)
50t = 36t + 3
50t - 36t = 3
14t = 3
t = 3%2F14 hrs is Sarah's travel time
Change to minutes 3%2F14*60 = 12.85 min say 13 min
then
13 + 5 = 18 min is Tracy's travel time who left at 8:00
S catches T at about 8:18
:
:
We can check this finding the distance each traveled, should be equal
50*13%2F60 = 10.8 mi
36*18%2F60 = 10.8 mi

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy?
----------------
In 5 minutes, Tracy goes (36/60)*5 miles = 3 miles
Sarah's speed relative to Tracy is 14 mi/hr (50 - 36)
It takes 3/14 hour to catch Tracy, =~ 13 minutes.
8:05 + 13 = 8:18