SOLUTION: A room has a perimeter of 48ft. The width is two-thirds of the length. What are the dimensions of the room?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A room has a perimeter of 48ft. The width is two-thirds of the length. What are the dimensions of the room?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 393791: A room has a perimeter of 48ft. The width is two-thirds of the length. What are the dimensions of the room?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

width is two-thirds of the length

Let x and (2/3)x represent the length and width respectively

 P = 2L + 2W

Question states***

  2x + 2(2/3)x = 48ft

solve for x

 2x + (4/3)x = 48ft    |multiplying each term by 3 so as all denominators = 1

 6x + 4x = 48ft*3

     10x = 144ft

       x = 14.4ft, the length.  the width is 2/3*14.4 = 9.6 ft

  28.4 + 18.2 = 47.6 = 48 ft