SOLUTION: Of four consecutive odd numbers the product of the second and the forth exceeds the product of the first and the third by 136. Find the numbers.

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Question 393694: Of four consecutive odd numbers the product of the second and the forth exceeds the product of the first and the third by 136. Find the numbers.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x, (x+2),(x+4),(x+6) represent the four consecutive odd numbers

Question States***Write as we Read

(x+2)(x+6) = x(x+4) + 136

solving for x

 x^2 + 8x + 12 = x^2 + 4x + 136

             4x = 124

              x = 31  Number are 31,33,35,37



CHECKING our Answer

 33*37 = 31*35 + 136