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1x-2y-2z+2w+-24.....1X-2Y-2Z+2W=24.....I........ASSUMING SO
0x-1y-2z-1w=-12...........II
EQN.I+2*EQN.II GIVES
X-2Y-2Z+2W-2Y-4Z-2W=24-24=0
X-4Y-6Z=0.............................III
SO WE HAVE 2 INDEPENDENT EQNS.IN 4 UNKNOWNS.HENCE THERE WILL BE INFINITE SOLUTIONS.TO GET ANY SET OF VALUES GIVE ARBITRARY VALUES TO ANY 2 UNKNOWNS AND FIND THE OTHER 2..SAY TAKE X=Y=0...WE GET FROM EQN.III
-6Z=0 AND Z=0
SUBSTITUTING IN EQN.II,WE GET W=12...LIKE THAT YOU CAN FIND ANY NUMBER OF SOLUTIONS.THERE IS NO UNIQUE ANSWER
find X:
Y:
W:
Z:
