SOLUTION: A poll found that 45% of the workers at the company take the bus instead of the car to work to save money. if 4 workers are selected at random what is the probability that at least

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Question 393165: A poll found that 45% of the workers at the company take the bus instead of the car to work to save money. if 4 workers are selected at random what is the probability that at least 1 worker take the bus instead of the car to work?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Note: The probability of x successes in n trials is: 

P = nCx* p%5Ex%2Aq%5E%28n-x%29 where p and q are the probabilities of success and failure respectively. 

In this case p(taking the bus)= .45 & q = .55

nCx = n%21%2F%28x%21%28n-x%21%29%29

P(out of 4, at least one takes bus) = 1-P(none taking bus) = 1 - (.55)^4

P(out of 4, at least one takes bus) = 1 - (.55)^4 = 1 - .0915 = .9085