SOLUTION: A container has 4 blue marbles, 5 red marbles, and 3 green marbles. if 3 marbles are drawn with replacement, what is the probability that all 3 will be green?
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-> SOLUTION: A container has 4 blue marbles, 5 red marbles, and 3 green marbles. if 3 marbles are drawn with replacement, what is the probability that all 3 will be green?
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Question 393162: A container has 4 blue marbles, 5 red marbles, and 3 green marbles. if 3 marbles are drawn with replacement, what is the probability that all 3 will be green? Answer by ewatrrr(24785) (Show Source):
Hi
12 marbles in all , 3 of which are green
P(drawing one green) = 3/12 = 1/4
With replacement, each draw is from bag of 12 marbles, 3 of which are green
P(3 green marbles) = 1/4* 1/4 * 1/4 = (1/4)^3 = 1/64
