Question 392689: Two cyclists start at the same point and travel in opposite directions. One travels 4 mph faster than the other. In 4 hours, they are 112 miles apart. Find how fast each is traveling.
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
Let r=rate of first cyclist
Then r+4=rate of other cyclist
In 4 hours, first cyclist travels 4r miles
In 4 hours, other cyclist travels 4(r+4) miles
And we are told that these two distances add up to 112 miles, sooooo:
4r+4(r+4)=112
4r+4r+16=112 subtract 16 from both sides
8r=112-16
8r=96
r=12 mph----rate of first cyclist
r+14=12+4=16 mph--rate of other cyclist
CK
In 4 hours, first cyclist travels 4*12=48 mi
In 4 hours other cyclist travels 4*16=64 mi
64+48=112
112=112
Hope this helps---ptaylor
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