SOLUTION: I will have four guests for bridge, for a total of five players. We play four hands and then rotate partners. One will sit out in each round. Is there a combination which woul

Algebra ->  Permutations -> SOLUTION: I will have four guests for bridge, for a total of five players. We play four hands and then rotate partners. One will sit out in each round. Is there a combination which woul      Log On


   



Question 392653: I will have four guests for bridge, for a total of five players. We play four hands and then rotate partners. One will sit out in each round. Is there a
combination which would have all players to play the same number of rounds; if so, how many rounds would be required?

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


You need to play 5 rounds so that each one of the 5 players sits out one round.


John

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