SOLUTION: "Find four consecutive odd integers such that the sum of the second and the fourth is 17 more than one-half the sum of the first and the third."

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: "Find four consecutive odd integers such that the sum of the second and the fourth is 17 more than one-half the sum of the first and the third."       Log On


   

Question 392609: "Find four consecutive odd integers such that the sum of the second and the fourth is 17 more than one-half the sum of the first and the third."
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
"Find four consecutive odd integers such that the sum of the second and the
fourth is 17 more than one-half the sum of the first and the third."
:
Four consecutive odd integers: x, (x+2), (x+4, (x+6)
:
(x+2) + (x+6) = .5(x + (x+4)) + 17
:
2x + 8 = .5(2x + 4) + 17
:
2x + 8 = x + 2 + 17
:
2x -x = 19 - 8
:
x = 11,
:
:
11, 13, 15, 17 are the integers
:
:
See if that is true in the original equation
13 + 17 = .5(11+15) + 17
30 = 13 + 17