SOLUTION: please explain or show work. this exactly how the question was written. using the exact values,find the value of: 12 sin 30degrees - 6 tan 45 degress + sec 45 degrees / 52

Algebra ->  Test -> SOLUTION: please explain or show work. this exactly how the question was written. using the exact values,find the value of: 12 sin 30degrees - 6 tan 45 degress + sec 45 degrees / 52      Log On


   



Question 392548: please explain or show work. this exactly how the question was written.
using the exact values,find the value of:
12 sin 30degrees - 6 tan 45 degress + sec 45 degrees / 52

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
All you need to know is the value+of the trigonometry functions at the special+angles.
For this problem, you need to know the following:

sin+%2830%29+deg+=+1%2F2

tan+%2845%29+deg+=+1

sec+%2845%29+=+sqrt%282%29

cos+%2830%29+=sqrt%283%29%2F2

sin+%2860%29+=+sqrt%283%29%2F2

so, you will have:

12+sin+30+deg+-+6+tan+45+deg+%2Bsec+45+deg%2F52

12+%281%2F2%29++-+6+%2A1+%2B+sqrt%282%29%2F52

6++-+6++%2B+sqrt%282%29%2F52

= sqrt%282%29%2F52

= %281.41%29%2F52

= 0.03