You can put this solution on YOUR website! From
x+3 2x-5
--- + ---
x+1 x-2
we can use what I call "the criss-cross method"
A C AD + BC
- + - = -------
B D BD
and so we get
[(x+3)(x-2) + (2x-5)(x+1)] / (x+1)(x-2) =
[x^2 + x - 6 + 2x^2 - 3x - 5] / (x+1)(x-2) =
(3x^2 - 2x - 11) / (x+1)(x-2)