SOLUTION: Suppose the Q-angles (measured standing) for a population of young adult women are normally distributed with a mean of 19 degrees and standard deviation of 8 degrees. Let us call t

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Question 392118: Suppose the Q-angles (measured standing) for a population of young adult women are normally distributed with a mean of 19 degrees and standard deviation of 8 degrees. Let us call this variable X.
What is the probability that a randomly chosen X-value is less than 24 degrees?
What is the probability that a randomly chosen X-value is greater than 24 degrees?


Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
*Note: z+=+blue%28X+-+mu%29%2Fblue%28sigma%29
z = (24-19)/8 = 5/8 = .626 |using the Excel NORMSDIST(0.626) function
P(z < 24) = .7343 P(z > 24) = 1 -.7343 = .2657