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Question 391895: When the digits of a two-digit number are reversed, the new number is 6 more than the original number. The units digit is twice the tens digit. What is the original number?
Answer by AnubhavRane(4)   (Show Source):
You can put this solution on YOUR website! The problem seem to have a typo somewhere, thus giving a strange answer.
Please check. But here is how you can solve it.
Let,
U = Digit in units place
T = Digit in tens place
But remember U and T are only DIGITs or the FACE values!
The place values will make the original number to be: 10T + U
After reversing the digits the new number will be: 10U + T
Now we have two relationships:
10U + T = 10T + U + 6 ...(I)
U = 2T ...............(II)
Substituting U = 2T from equation (II) to equation (I)
10 (2T) + T = 10T + (2T) + 6
20T + T = 12T + 6
21T - 12T = 6
T = 6/9 ......But this cannot be a DIGIT.
So the given problem is not correct.
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