Question 39179: I am having some difficulty identifying the correct answer, it is actually multiple choice, but even the choices do not make sense.Here is the problem with possible solutions.
f(x)=2x^3+x^2+3x+8
List all of the potential rational zeros of the polynomial function. Do not attempt to find the zeros. The choices are:
a)+-2,+-4,+-8,+-1/2,+-7/2
b)+-2,+-4,+-8,+-16,+-1/2
c)0,+-1,+-2,+-4,+-1/2
d)+-1,+-2,+-4,+-8, +-1/2
Answer by Nate(3500)   (Show Source):
You can put this solution on YOUR website! 
Define "a" as the factors of the constant ....
a:1,2,4,8
Define "b" as the factors of the leading coefficient ....
b:1,2
The possible zeros are defined as +-(a/b)
Should be:
+-1,+-2,+-4,+-8,+-(1/2)
The answer is (D).
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