SOLUTION: Suppose the variable X has a normal distribution with mean 36 inches and standard deviation 2 inches. what X value represents the 50th percentile of this distribution, that is what

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose the variable X has a normal distribution with mean 36 inches and standard deviation 2 inches. what X value represents the 50th percentile of this distribution, that is what      Log On


   

Question 391757: Suppose the variable X has a normal distribution with mean 36 inches and standard deviation 2 inches. what X value represents the 50th percentile of this distribution, that is what X value will have 50% of the distribution to its left?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

variable X with a normal distribution with mean 36 inches and standard deviation 2 inches       

finding the X value approximating the 50th percentile of this distribution

*Note: z+=+blue%28x+-+mu%29%2Fblue%28sigma%29

 NORMSINV(0.50)= 0    | area illustrated to the left of center - the mean value

   z= (X - 36)/2 = 0   

       X = 36, the mean value