SOLUTION: What is the elimination method 2r-5s=-29 and 5r+2s=58?

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Question 391673: What is the elimination method 2r-5s=-29 and 5r+2s=58?
Answer by mananth(16946) About Me  (Show Source):
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What is the elimination method 2r-5s=-29 and 5r+2s=58?
...
2r-5s=-29........................1
5r+2s=58.........................2
..
multiply (1)by 5 & (2) by -2
10r-25s=-145
-10r-4s=-116
Add them up
-25s-4s=-145-116
-29s==-261
/-29
highlight%28s=+9%29%29
..
plug value of s in (1)
2r-5*9=-29
2r-45=-29
2r=45-29
2r=16
/2
highlight%28r=8%29%29
m.ananth@hotmail.ca