SOLUTION: i need your help on how to graph these graph y=0.5x-3 draw a parallel line to y=0.5x-3 that goes through the points (4,6) write an equation draw a line that is perpendicular to y=0

Algebra ->  Graphs -> SOLUTION: i need your help on how to graph these graph y=0.5x-3 draw a parallel line to y=0.5x-3 that goes through the points (4,6) write an equation draw a line that is perpendicular to y=0      Log On


   



Question 391648: i need your help on how to graph these graph y=0.5x-3 draw a parallel line to y=0.5x-3 that goes through the points (4,6) write an equation draw a line that is perpendicular to y=0.5x-3 and has a y - intercept of 4
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
y=0.5x-3 is a straight line in the form of y=mx+b, with m being the slope and b the y-intercept
a line parallel to this line would have the same slope but may have a different y-intercept
The paallel line going through (4,6) would have a slope of .5 or 1/2
To find the y-intercept, insert the known slope of 1/2 and (x,y) values of (4,6), then solve for b
6=(1/2)*4+b
b=6-2=4
equation of parallel line: y=(1/2)x+4
The perpendicular line would have a slope = negative reciprocal of the slope of the given line=-2
with the y-intercept given,
equation of the perpendicular line: y=-2x+4
see graphs of these lines below
+graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+.5x%2B4%2C-2x%2B4%29+