SOLUTION: Chris has ridden 10 miles going 12 miles per hour.  How many more minutes must he ride to go 60 miles?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Chris has ridden 10 miles going 12 miles per hour.  How many more minutes must he ride to go 60 miles?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 391618: Chris has ridden 10 miles going 12 miles per hour.  How many more minutes must he ride to go 60 miles?
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
60-10=50 miles remain
s*t=d
12t=50
t=50/12
=25/6 hrs
= 25/6 * 60 = 250 minutes
.
Ed