SOLUTION: A white-tailed deer is running from a black bear at 20 mph. It is 1/3 mile in front of the bear. The bear is running at 30 mph. How long will it take the bear to catch the deer? As

Click here to see ALL problems on Average

Question 391587: A white-tailed deer is running from a black bear at 20 mph. It is 1/3 mile in front of the bear. The bear is running at 30 mph. How long will it take the bear to catch the deer? Assume both continue running at the same pace.
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A white-tailed deer is running from a black bear at 20 mph. It is 1/3 mile in front of the bear. The bear is running at 30 mph. How long will it take the bear to catch the deer? Assume both continue running at the same pace.
--------------
Deer Data:
rate = 20 mph ; time = x hrs. ; distance = 20x miles
-----
Bear Data:
rate = 30 mph ; time = x hrs. ; distance = 30x miles
----
Equation:
bear distance - deer distance = 1/3 mile
----
30x - 20x = 1/3
10x = 1/3
x = 1/30 hr.
x = (1/30)(60 minutes) = 2 minutes
=========================
Cheers,
Stan H.

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
A white-tailed deer is running from a black bear at 20 mph. It is 1/3 mile in front of the bear. The bear is running at 30 mph. How long will it take the bear to catch the deer? Assume both continue running at the same pace.
--------------------
The bear's speed relative to the deer is 10 mph (30 - 20).
d = rt
t = d/r
t = (1/3)/10
t = 1/30 hour
t = 2 minutes