| 
 
 
| Question 391376:  A hyperbola has vertices  (8,0)and (-8,0)Its foci are located at  (√(89),0) and(-√(89),0) identify the equation of this hyperbola. I honestly have no Idea how to solve this please help.Thanks in advance. :)
 Answer by ewatrrr(24785)
      (Show Source): 
You can put this solution on YOUR website! Hi,
 vertices on the x-axis: (8,0)and (-8,0) Hyperbola opens right and left.
 Standard Form of an Equation of an Hyperbola is
   where Pt(h,k) is a center  with vertices 'a' units right and left of center
 and asymptotes that pass thru the center with slope = ± b/a
 In this example: center is (0,0) with a = 8
 x^2/8^2 - y^2/b^2 = 1
 foci (c,0) and (-c,0) are (sqrt(89), 0),-sqrt(89), 0 }}}
 c, the distance from the center to the foci
 c^ = a^2 + b^2
 
  = 8^2 + b^2 89 = 64 + b^2
 25 = b^2
 b = ± 5
 x^2/8^2 - y^2/5^2 = 1
 
   
 
  
 | 
  
 | 
 |