SOLUTION: ay + 3a + 2y + 6 / ay + 3a + 5y + 15

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Question 39135: ay + 3a + 2y + 6 / ay + 3a + 5y + 15
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
We factor top and bottom "by grouping," so from
ay + 3a + 2y + 6 / ay + 3a + 5y + 15 =
a(y + 3) + 2(y + 3) / a(y + 3) + 5(y + 3) =
(a + 2)(y + 3) / (a + 5)(y + 3) =
(a + 2) / (a + 5)