SOLUTION: Twice the first of three consecutive integers minus the third equals 58.Find the three integers

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Question 391333: Twice the first of three consecutive integers minus the third equals 58.Find the three integers
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x = 1st
x+2 = 3rd
-------
2x - (x+2) = 58
x-2 = 58
x = 60

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

Let x,(x+1),(x+2) represent the three consecutive integers

question states****

2x - (x+2) = 58

2x - x- 2) = 58

    x = 60

the three consecutive integers are 60,61,62



CHECKING our Answer

 120 - 62 = 58