Question 391265: 2^-3x^2z^-7
Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! 2^(-3)x^(2)z^(-7)
Remove the negative exponent by rewriting 2^(-3)x^(2)z^(-7) as (x^(2)z^(-7))/(2^(3)). A negative exponent follows the rule a^(-n)=(1)/(a^(n)).
(x^(2)z^(-7))/(2^(3))
Cubing a number is the same as multiplying the number by itself 3 times (2*2*2). In this case, 2 cubed is 8.
(x^(2)z^(-7))/(8)
Remove the negative exponent in the numerator by rewriting (x^(2)z^(-7))/(8) as (x^(2))/(8(z^(7))). A negative exponent follows the rule: a^(-n)=(1)/(a^(n)).
(x^(2))/(8(z^(7)))
Remove the negative exponent in the denominator by rewriting (x^(2)z^(-7))/(8) as (x^(2))/(8(z^(7))). A negative exponent follows the rule: a^(-n)=(1)/(a^(n)).
(x^(2))/(8z^(7))
|
|
|
