SOLUTION: Please help me with rewrite the expression using rational exponents. (index of 7 on sqrt (3a^4b))^5 Honestly, I have no idea where to even start on this thing. Thank you so m

Algebra ->  Rational-functions -> SOLUTION: Please help me with rewrite the expression using rational exponents. (index of 7 on sqrt (3a^4b))^5 Honestly, I have no idea where to even start on this thing. Thank you so m      Log On


   



Question 391259: Please help me with rewrite the expression using rational exponents.
(index of 7 on sqrt (3a^4b))^5
Honestly, I have no idea where to even start on this thing.
Thank you so much for any help!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(index of 7 on sqrt (3a^4b))^5
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The index tells you to find the 7th root.
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7th rt. of (3^5*a^20*b^5)
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= 7th rt of (a^14*243a^6b^5)
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= 7th rt of (a^14) * 7th rt of(243a^6b^5)
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= a^2*7th rt of(243a^6b^5)
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Cheers,
Stan H.