SOLUTION: Marie and Tony went shopping together. Marie bought 2L of milk and 10 oranges for $3.44. Tony bougth 3L of milk and 8 otanges for 3.69 What was the cost of of one liter of milk? o

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Marie and Tony went shopping together. Marie bought 2L of milk and 10 oranges for $3.44. Tony bougth 3L of milk and 8 otanges for 3.69 What was the cost of of one liter of milk? o      Log On


   

Question 391249: Marie and Tony went shopping together. Marie bought 2L of milk and 10 oranges for $3.44. Tony bougth 3L of milk and 8 otanges for 3.69 What was the cost of of one liter of milk? of one orange?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1) 2m+%2B+10r+=+3.44
(2) 3m+%2B+8r+=+3.69
Multiply both sides of (1) by 3
Multiply both sides of (2) by 2
and subtract (2) from (1)
(1) 6m+%2B+30r+=+10.32
(2) -6m+-+16r+=+-7.38
14r+=+2.94
r+=+.21
Substitute this in (1)
(1) 2m+%2B+10%2A.21+=+3.44
2m+%2B+2.1+=+3.44
2m+=+1.34
m+=+.67
1 liter of milk is 67 cents
1 orange is 21 cents