SOLUTION: The perimeter of a rectangle is 18 inches. The length is twice the width. Please find the length and the width. (I worked at this thing but I got no where because I can only make o

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The perimeter of a rectangle is 18 inches. The length is twice the width. Please find the length and the width. (I worked at this thing but I got no where because I can only make o      Log On


   

Question 391234: The perimeter of a rectangle is 18 inches. The length is twice the width. Please find the length and the width. (I worked at this thing but I got no where because I can only make one equation x+x+y+y=18 but in order to graph it on my worksheet I need another equation but I don't see another one.)
Found 2 solutions by NOEL_33, richard1234:
Answer by NOEL_33(3) About Me  (Show Source):
You can put this solution on YOUR website!
You could do 4.5+4.5+4.5+4.5=18 or 4 & 1/2, but four times

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
If x is the length, then the width y must be equal to 2x. So, y = 2x and we can substitute y to obtain

x + x + 2x + 2x = 18

6x = 18

x = 3 --> y = 2(3) = 6.