SOLUTION: how much of an 85% solution of antifreeze should be added to 5L of a 45% solution to produce a 60% solution

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Question 391191: how much of an 85% solution of antifreeze should be added to 5L of a 45% solution to produce a 60% solution
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = L of 85% solution to be added
.85a = L of additive
given:
.45%2A5+=+2.25 L of additive in 45% solution
-----------------
In words:
(L of additive)/(L of solution) = 60%
%28.85a+%2B+2.25%29%2F%28a+%2B+5%29+=+.6
.85a+%2B+2.25+=+.6%2A%28a+%2B+5%29
.85a+%2B+2.25+=+.6a+%2B+3
.25a+=+.75
a+=+3
3 Liters of 85% solution should be added
check:
%28.85a+%2B+2.25%29%2F%28a+%2B+5%29+=+.6
%28.85%2A3+%2B+2.25%29%2F%283+%2B+5%29+=+.6
%282.55+%2B+2.25%29%2F8+=+.6
4.8%2F8+=+.6
4.8+=+4.8
OK