SOLUTION: Use the steps below to solve the following problem. Three brothers have ages that are consecutive multiples of five. The sum of their ages two years ago was 69. Find their ages.
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-> SOLUTION: Use the steps below to solve the following problem. Three brothers have ages that are consecutive multiples of five. The sum of their ages two years ago was 69. Find their ages.
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Question 391086: Use the steps below to solve the following problem. Three brothers have ages that are consecutive multiples of five. The sum of their ages two years ago was 69. Find their ages.
Steps:
a. Let the youngest brother's age be "n". Write an expression for the age of each of the other brothers.
b. Use your answer from (a) to write an expression for the age of each of the brotherss two years ago.
c. Use your answer from (b) to write an expression for the sum of the brother's ages two years ago. Simplify the expression.
d. For what value of "n" will the expression from (c) equal 69?
e. Use the value of "n" you found in part (d) to find the age od each of the brothers now.
f. Check: First check that each age you found from (e) is a multiple of five. Then find the ages of the two brothers two years ago. Check that the sum is 69. Answer by solver91311(24713) (Show Source):
