SOLUTION: One focus is located at (-6,-10.32).Find the other focus defined by this equation: (x+6)^2/25+(y+7)^2/36=1.I have no Idea how to do this.please help,I'd appreciate it.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: One focus is located at (-6,-10.32).Find the other focus defined by this equation: (x+6)^2/25+(y+7)^2/36=1.I have no Idea how to do this.please help,I'd appreciate it.      Log On


   

Question 390977: One focus is located at (-6,-10.32).Find the other focus defined by this equation: (x+6)^2/25+(y+7)^2/36=1.I have no Idea how to do this.please help,I'd appreciate it.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

the foci are both the same distance from the center at(-6,-7) along the major axis

sketching it out: 

question states***

one foci has y value = -10.32 (-7 -3.32)   |foci is Pt(-6 ,-10.32)

the other has a y value = -3.68 (-7+3.32)    |foci is Pt(-6,-3.68)