SOLUTION: Can someone help me do this problem step by step so I can understand it. I am confused. Thank you so much. A picture has a height that is 4/3 its width. It is to be enlarged to

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Can someone help me do this problem step by step so I can understand it. I am confused. Thank you so much. A picture has a height that is 4/3 its width. It is to be enlarged to      Log On

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Question 390944: Can someone help me do this problem step by step so I can understand it. I am confused. Thank you so much.
A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?
Thank you so much I just do not understand.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A picture has a height that is 4/3 its width.
It is to be enlarged to have an area of 192 square inches.
What will be the dimensions of the enlargement?
:
Let x = the width of the enlargement
then
4%2F3x = the height of the enlargement
:
The area is height * width, therefore
x*4%2F3x = 192
which is
4%2F3x^2 = 192
multiply both sides by 3 to get rid of the denominator
4x^2 = 192 * 3
4x^2 = 576
Divide both sides by 4 and you have
x^2 = 144
x = sqrt%28144%29
x = 12 is width
then
4%2F3 * 12 = 16 is the height
:
:
We can confirm this by finding the area with these values
12 * 16 = 192
:
Not that hard, right?